Monday, November 13, 2017

Mathematics today.....


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                                           Mathematics
See this:

See solution for the  question: SINX-COSX
SINX-COSX
Take the square of both sides(SINX)2 – (COSX)2 0.2
RecalledSIN2 X +COS2X 1
SIN2X-(1-SIN2X) = 0.2SIN2X+SIN2X=0.2+12SIN2X =1.2Divide both sides by two2SIN2X ÷2  = 1.2 ÷2SIN2X =0.6Take the square root of both sidesSINX =0.7746X = ARCSIN(0.7746)X =  50.7684 DegreeApprox. 51 Degree 





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